if let

For some use cases, when matching enums, match is awkward. For example:

#![allow(unused)]
fn main() {
// Make `optional` of type `Option<i32>`
let optional = Some(7);

match optional {
    Some(i) => println!("This is a really long string and `{:?}`", i),
    _ => {},
    // ^ Required because `match` is exhaustive. Doesn't it seem
    // like wasted space?
};

}

if let is cleaner for this use case and in addition allows various failure options to be specified:

In the same way, if let can be used to match any enum value:

// Our example enum
enum Foo {
    Bar,
    Baz,
    Qux(u32)
}

fn main() {
    // Create example variables
    let a = Foo::Bar;
    let b = Foo::Baz;
    let c = Foo::Qux(100);
    
    // Variable a matches Foo::Bar
    if let Foo::Bar = a {
        println!("a is foobar");
    }
    
    // Variable b does not match Foo::Bar
    // So this will print nothing
    if let Foo::Bar = b {
        println!("b is foobar");
    }
    
    // Variable c matches Foo::Qux which has a value
    // Similar to Some() in the previous example
    if let Foo::Qux(value) = c {
        println!("c is {}", value);
    }

    // Binding also works with `if let`
    if let Foo::Qux(value @ 100) = c {
        println!("c is one hundred");
    }
}

Another benefit is that if let allows us to match non-parameterized enum variants. This is true even in cases where the enum doesn't implement or derive PartialEq. In such cases if Foo::Bar == a would fail to compile, because instances of the enum cannot be equated, however if let will continue to work.

Would you like a challenge? Fix the following example to use if let:

// This enum purposely neither implements nor derives PartialEq.
// That is why comparing Foo::Bar == a fails below.
enum Foo {Bar}

fn main() {
    let a = Foo::Bar;

    // Variable a matches Foo::Bar
    if Foo::Bar == a {
    // ^-- this causes a compile-time error. Use `if let` instead.
        println!("a is foobar");
    }
}

See also:

enum, Option, and the RFC