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Translate library/math.po rst: 87-102, 239-374 #992

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Carisa-Li Oct 6, 2024
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rst: 87-102, 239-374
Carisa-Li Oct 21, 2024
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Update library/math.po 
Co-authored-by: Payon <[email protected]>
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@Carisa-Li @ken71301
Carisa-Li and ken71301 authored Nov 9, 2024
commit 76d05a06a35eac786510522516fbe54d56c5751e
2 changes: 1 addition & 1 deletion library/math.po
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Expand Up @@ -436,7 +436,7 @@ msgstr ""
"回傳 *x* 對 *y* 根據 IEEE 754 定義的餘數。對有限數 *x* 及有限非零數 *y*，該餘"
"數值為 ``x - n*y``，``n`` 是最接近 ``x / y`` 精確值的整數。若 ``x / y`` 剛好"
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quotient 沒翻到，然後這句也沒有精確度歐

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我是將the exact value of the quotient x / y合翻為x / y精確值
quotient主要是擔心商可能會誤解為僅指運算結果的整數部分，這部分我會再思考一下

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這邊的 difference 應該不是餘數?
看起來比較接近
"這是 x - n*y 的另一種寫法" 之類的

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因為上一句定義了x,y兩數，所以我將this翻為該餘數值與第一句的根據 IEEE 754 定義的餘數對應，此處的difference我想應該是指差(減法運算的結果)，這部分我會再想一下

"位於兩個連續整數的正中間，``n`` 為最接近的 *偶* 數。因此該餘數 ``r = "
"remainder(x, y)`` 必滿足 ``abs(r) <= 0.5 * abs(y)``。"
"remainder(x, y)`` 總是滿足 ``abs(r) <= 0.5 * abs(y)``。"

#: ../../library/math.rst:301
msgid ""
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